The motor adjusts its rpm until the counter emf generated in its coils is equal to the applied voltage. There is, unfortunately, a drop across the internal resistance of the motor, which causes the rpm to drop in relation to the load. In other words, the larger the load, the larger the drop across the internal resistance and the lower the rpm. * This circuit provides a kind of compensation for the internal resistance of the motor: when the current drawn by the motor rises, the supply voltage is increased automatically to counter the fall in rpm. The circuit is based on an enhanced voltage regulator that consists of IC1 and Tl, which provides a reasonably large output current (even small drills draw 2-to-5 A). The "onset" supply voltage, and thus the rpm, is set by P2. Because of emitter resistance Rl, the currents through IC1 and Tl will be related to one another in the ratio that is determined by Rl and R2. Owing to this arrangement, the internal short-circuit protection of IC1 will also, indirectly, provide some protection to Tl. As soon as the current drawn exceeds a certain value, T2 will be switched on. This results in a base current for T3 so that R5 is in parallel (more or less) with R6. This arrangement automatically raises the output voltage to counter a threatened drop in rpm. The moment at which this action occurs is set by PI, so this circuit can be adapted pretty precisely to the motor used. If only very small motors are likely to be used, the power supply (transformer and bridge rectifier) can be rated more conservatively. As a guide, the current in the transformer secondary should be about 1.5 times the maximum dc output current.
An Electronic Circuits Blog with Latest and rear Electronic Circuits for Hobby and Projects
Saturday, December 22, 2012
Drill Controller | Mini-Drill Controller Circuit
This circuit is intended as a revolution control for small dc motors as fitted, for instance, in small electric drills (such as used for precision engineering and for drilling boards, among others). The behavior of these motors, which are normally permanent magnet types, is comparable to that of independently powered motors. In theory, the rpm of these motors depends solely on the applied voltage.
The motor adjusts its rpm until the counter emf generated in its coils is equal to the applied voltage. There is, unfortunately, a drop across the internal resistance of the motor, which causes the rpm to drop in relation to the load. In other words, the larger the load, the larger the drop across the internal resistance and the lower the rpm. * This circuit provides a kind of compensation for the internal resistance of the motor: when the current drawn by the motor rises, the supply voltage is increased automatically to counter the fall in rpm. The circuit is based on an enhanced voltage regulator that consists of IC1 and Tl, which provides a reasonably large output current (even small drills draw 2-to-5 A). The "onset" supply voltage, and thus the rpm, is set by P2. Because of emitter resistance Rl, the currents through IC1 and Tl will be related to one another in the ratio that is determined by Rl and R2. Owing to this arrangement, the internal short-circuit protection of IC1 will also, indirectly, provide some protection to Tl. As soon as the current drawn exceeds a certain value, T2 will be switched on. This results in a base current for T3 so that R5 is in parallel (more or less) with R6. This arrangement automatically raises the output voltage to counter a threatened drop in rpm. The moment at which this action occurs is set by PI, so this circuit can be adapted pretty precisely to the motor used. If only very small motors are likely to be used, the power supply (transformer and bridge rectifier) can be rated more conservatively. As a guide, the current in the transformer secondary should be about 1.5 times the maximum dc output current.
The motor adjusts its rpm until the counter emf generated in its coils is equal to the applied voltage. There is, unfortunately, a drop across the internal resistance of the motor, which causes the rpm to drop in relation to the load. In other words, the larger the load, the larger the drop across the internal resistance and the lower the rpm. * This circuit provides a kind of compensation for the internal resistance of the motor: when the current drawn by the motor rises, the supply voltage is increased automatically to counter the fall in rpm. The circuit is based on an enhanced voltage regulator that consists of IC1 and Tl, which provides a reasonably large output current (even small drills draw 2-to-5 A). The "onset" supply voltage, and thus the rpm, is set by P2. Because of emitter resistance Rl, the currents through IC1 and Tl will be related to one another in the ratio that is determined by Rl and R2. Owing to this arrangement, the internal short-circuit protection of IC1 will also, indirectly, provide some protection to Tl. As soon as the current drawn exceeds a certain value, T2 will be switched on. This results in a base current for T3 so that R5 is in parallel (more or less) with R6. This arrangement automatically raises the output voltage to counter a threatened drop in rpm. The moment at which this action occurs is set by PI, so this circuit can be adapted pretty precisely to the motor used. If only very small motors are likely to be used, the power supply (transformer and bridge rectifier) can be rated more conservatively. As a guide, the current in the transformer secondary should be about 1.5 times the maximum dc output current.
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